решите уравнение sin9xcos2x - cos9xsin2x = - sqrt(3)/2 - №20826837

решите уравнение sin9xcos2x - cos9xsin2x = - sqrt(3)/2
- Предмет:
  Алгебра
- Автор:
  hayleevkzk
- 6 лет назад

Ответы 2

sin(9x-2x)=-√3/2sin7x=-√3/27x=(-1)^(n+1)*π/3+πnx=(-1)^(n+1)*π/21+πn/7,n∈z
- Автор:
  rebeca
- 6 лет назад
- 0
sin(9x-2x)=√3/2 sin7x=√3/2 7x=(-1)ⁿπ/3+πkx=(-1)ⁿπ/21+πk/7 k∈Z
- Автор:
  rollins
- 6 лет назад
- 0
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