Решите систему уравнений [tex] \left \{ {{x+y= \frac{ \pi }{2} } \atop {cosx-cosy=- \sqrt{2} }} ight. [/tex] в ответе запишите значение y∈[0; 360]в градусах.

x=π/2-ycos(π/2-y)-cosy=-√2-2sin(π/4-y)*sinπ/4=-√2-2*√2/2*sin(π/4-y)=-√2sin(π/4-y)=1cos(π/4+y)=1π/4+y=2πny=-π/4+2πn⇒x=3π/4+2πny=7π/4=315гр∈(0;360)