Срочно!

(1–x+x^2)(6+x–x^2)=10

(1–x+x^2)(6+x–x^2)=10 (x²-x+1)(x²-x-6)=-10x²-x-6=a⇒x²-x+1=a+7a(a+7)+10=0a²+7a+10=0a1+a2=-7 U a1*a2=10a1=-5⇒x²-x-6=-5x²-x-1=0D=1+4=5x1=(1-√5)/2 U x2=(1+√5)/2a2=-2⇒x²-x-6=-2x²-x-4=0D=1+16=17x1=(1-√17)/2 U x2=(1+√17)/2