решить систему {y^2-2x^2=8 {x+y=6

Х + y = 6 y = 6 - x y^2 = ( 6 - x )^2 = 36 - 12x + x^2 y^2 - 2x^2 = 8 y^2 = 2x^2 + 8 2x^2 + 8 = 36 - 12x + x^2 X^2 + 12x - 28 = 0 D = 144 + 112 = 256 = 16^2 X1 = ( - 12 + 16 ) : 2 = 2 X2 = ( - 12 - 16 ) : 2 = - 14 y = 6 - x y1 = 6 - 2 = 4 y2 = 6 + 14 = 20 Ответ ( 2 ; 4 ) ; ( - 14 ; 20 )