Решите неравенство [tex] -4 \leq 3^{x^2-2x-1}-5 \leq 4[/tex]

-4+5≤3^(x²-2x-1)≤4+51≤3^(x²-2x-1)≤9{x²-2x-1≥0{x²-2x-1≤21)D=4+4=8x1=(2-2√2)/2=1-√2 U x2=1+√2x≤1-√2 U x≥1+√22)x²-2x-3≤0x1+x2=2 u x1*x2=-3x1=-1 u x2=3-1≤x≤3x∈[-1;1-√2]