1) (3/7)^(3x-7)=(7/3)^(7x-3)
2) 3^x*(1/3)^(x-3)=(1/27)^x

http://znanija.com/task/21316512

http://znanija.com/task/21316512

Ответ******************£££££******

( 3/7 ) ^ ( 3х - 7 ) = ( 7/3 ) ^ ( 7х - 3 ) ( 3/7 ) ^ ( 3х - 7 ) = ( 3/7 ) ^ ( 3 - 7х ) 3х - 7 = 3 - 7х 10х = 10 Х = 1 ••••••••••••••3^х•( 1/3 )^( Х - 3 ) = ( 1/27 ) ^ Х 3^х • 3^( 3 - Х ) = 3 ^ ( - 3х ) 3 ^ ( Х + 3 - Х ) = 3 ^ ( - 3х ) 3 ^ 3 = 3 ^ ( - 3х ) 3 = - 3х Х = - 1