1/sin^2x-1/cos(3П/2-x)=2 на [П; 5П/2]

1/sin²x+1/sinx=22sin²x-sinx-1=0sinx=a2a²-a-1=0D=1+8=9a1=(1-3)/4=-1/2⇒sinx=-1/2⇒x=(-1)^n+1*π/6+πna2=(1+3)/4=1⇒sinx=1⇒x=π/2+2πnx=5π/2;7π/6;11π/6