sin(pi/18-8x)＝1
помогите решить.срочно надо

РешениеSin(π/18-8x)＝1- sin(8x - π/18) = 1sin(8x - π/18) = - 18x - π/18 = - π/2 + 2πk, k ∈ Z8x = - π/2 + π/18 + 2πk, k ∈ Z8x = - 8π/18 + 2πk, k ∈ Zx = - π/18 + πk/4, k ∈ Z