(√320-3∛24)(√45- 2∛81)
(sin∝-cos∝)2+ (sin∝+cos∝)2
у=cos(0,5x- π/2)
(lg2+lg3)/(lg3,6+1)
cos^(2)x-4cosx+3=0

1(8√5-3*2∛3)(3√5-2*3∛3)=(8√5-6∛3)(3√5-6∛3)=120-48√5∛3-18√5∛3+36∛9==120-66√5∛3+36∛92sin²a-2sinacosa+cos²a+sin²a+2sinacosa+cos²a=2(sin²a+cos²a)=23y=cos(0,5x-π/2)=cos(π/2-0,5x)=sin0,5x4(lg2+lg3)/(lg3,6+lg10)=lg6/lg36=log(36)6=1/25cosx=aa²-4a+3=0a1+a2=4 U a1*a2=3a1=1⇒cosx=1⇒x=2πn,n∈za2=3⇒cosx=3>1 нет решения