ПОМОГИТЕ!!!Решить систему:
x-y=П/2
Sinx+siny = - корень из 2

1) x-y=π/2, 2) sinx+siny =-√2;1) x=π/2+y;2) sin(π/2+y)+siny=-√2;2sin(π/4+y)cosπ/4=-√2;sin(π/4+y)*√2/2=-√2/2;sin(π/4+y)=-1;π/4+y=-π/2+2πn, n∈Z;y=-π/2-π/4+2πn, n∈Z;y=-3π/4+2πn, n∈Z.1) x=π/2-3π/4+2πn, n∈Z;x=-π/4+2πn, n∈Z.Ответ: (-π/4+2πn, n∈Z; -3π/4+2πn, n∈Z)