Решите систему
2у-х=7
Х²-ху-у²=29

x = 2y - 7(2y - 7)^2 - (2y - 7) - y^2 = 294y^2 - 28y + 49 -2y + 7 -y^2 = 293y^2 - 30y + 27 =0 /3y^2 - 10y + 9 = 0D1 = 25 - 1 × 9 = 16y1 = 9 y2 = 1 x1 = 2 × 9 - 7 = 11x2 = 2 × 1 - 7 = -5