решить систему уравнений {6x+3=8x-3(2y-4) 2(2y-3y)-4x=2y-8

6X + 3 = 8X - 6Y + 12

2X - 6Y + 8 = 0

///////////////////////

- 2Y - 4X - 2Y + 8 = 0

- 4Y - 4X + 8 = 0

-X - Y - 2 = 0

//////////////////

2X - 6Y + 8 = 0

- X - Y - 2 = 0

//////////////

X - 7Y + 6 = 0

X = 7Y - 7

///////////////

-2Y -4*(7Y - 7) - 2Y + 8 = 0

- 4Y - 28Y + 28 + 8 = 0

- 32Y = - 36

Y = 1.125

//////////////

X = 7Y - 7 = 7.875 - 7 = 0.875