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Найти сумму первых шести членов геометрической прогрессии, если b1=2, q = 3
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Предмет:
Алгебра -
Автор:
numbershdva - 5 лет назад
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Ответы 1
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Формула суммы n-первых членов геометрической прогрессии S=(b1(q^n-1))\(q-1)Подставляем:S=(2*(3^6-1))\3-1S=728
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Автор:
flybyelba - 5 лет назад
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