log3(основание)^2x-log3x-6=0

log^2 (3)х -log(3)х-6=01)log(3)х = - 2х=3^(-2)х1=1\9log(3)х=3х=3^3х2=27

log₃²x - log₃x -6 = 0a = log₃x a² - a - 6 = 0a₁=-2             a₂=3log₃x=-2       log₃x=3  x₁=3⁻²=1/9       x₂=3³=27