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Определить модуль геометрической прогрессии, в которой разность второго и первого элементов равна 70, а разность четвертого и третьего элементов равна 1120
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b1q-b1=70 b1(q-1)=70 b1q³-b1q²=1120 b1q²(q-1)=112070q²=1120 q²=16 q=+-4
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Автор:
brunowalls - 6 лет назад
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