решите уравнение -x-2+3(x-3)=3(4-x)-3

-х-2+3(х-3)=3(4-х)-3-х-2+3х-9=12-3х-3-х+3х+3х=12-3+2+95 х=20х=20:5х=4

-Х-2+3(Х-3) = 3(4-Х)-3-Х-2+3Х-9 = 12-3х-3-Х-2+3Х-9-12+3Х+3 =05Х-20 =05Х = 20Х = 20:5Х = 4-4-2+3(4-3) = 3(4-4)-3-3=-3