ПОМОГИТЕ, СРОЧНО!!!!!
cos2x=sinx(sinx-cosx)

cos2x=sinx-cosx cos²x-sin²x+(cosx-sinx)=0 (cosx-sinx)(cosx+sinx)+(cosx-sinx)=0 (cosx-sinx)(cosx+sinx+1)=0 cosx=sinx => x=π/4+πn cosx+sinx=-1 sin(x+π/4)=-1/√2 x+π/4=(-1)^(n+1) π/4+πk x=-π/4+(-1)^(n+1) π/4+πk

Cos^2x-sin^2x-sin^2x+sin x cos x=0;cos^2 x-2sin^2 x+sin x cos x=0; разделим все на cos^2x не =0;1-2tg^2х+tg x=0;2tg^2x-tg x-1=0;D=9; tgx=-1/2;tgx=1;x=-arctg 1/2+Пn;x=П/4+ пn