найдите 8-й и 13-й члены геометрической прогрессии если их сумма равна 21 а произвадение 16-го и 5-го членов этой прогрессии равно 104
Предмет:
АлгебраАвтор:
doogieyg20b8+b13=21
b16*b5=104
b1*q^7+b1q^12=21
b1*q^12*b1*q^7=104 => b8*b13=104
b8=x
b13=y
{x+y=21
{xy=104
{x=21-y
{21y-y^2=104
{y^2 -21y+104=0
D= 441-4*104=441-416=V25=5
y=13
y=8
Ответ b8=8. b13=13
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