Дано уравнение х^2 + 5x - 4 = 2 с корнями х1 и х2. составить квадратное уравнение с корнями у1=

Дано уравнение х^2 + 5x - 4 = 2 с корнями х1 и х2. составить квадратное уравнение с корнями у1= х1/х2 и у2= х2/х1
- Предмет:
  Алгебра
- Автор:
  french fryu88q
- 5 лет назад

Ответы 1

x^2+5x-6=0;D=49; x1=1; x2=-6;y1=-1/6; y2=-6;будем составлять уравнение по формуле:а(x-x1)(x-x2), где x1, x2 - корни, a - коэффицент перед x^2в данном случае:a(x+1/6)(x+6)(a) может быть любое число, но для удобства вычисления: a=6;(6x+1)(x+6)=6x^2+36x+x+6=6x^2+37x+6Ответ: 6x^2+37x+6=0
- Автор:
  ingram
- 5 лет назад
- 0
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Дано уравнение х^2 + 5x - 4 = 2 с корнями х1 и х2. составить квадратное уравнение с корнями у1= х1/х2 и у2= х2/х1

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