Решите уравнение 5y^4-8y^2+3=0

5y^4 - 8y^2 + 3 = 0 y^2 = t5t^2 - 8t + 3 = 0 D = 64  - 4*3*5 = 2^2t1 = ( 8 + 2)/10 = 10/10 = 1t2 = ( 8 - 2)/10 = 3/5 = 0.6y^2 = 1y1 = - 1y2 = 1y^2 = 0.6y3 = - √0.6y4 = √0.6

5y⁴-8y²+3=0y²=a5a²-8a+3=0D=64-60=4a=6:10=0,6a=10:10=1y²=a1)y²=0,6y=√0,6y=-√0,62)y²=1y=1; y=-1