(х+1)^2 (х^2+2х)=0
(Х^2+3х+1)(х^2+3х+3)=-1
(Х^2-4х+1)(х^2-4х+2)=12
Решите пжж

всё

(х+1)^2 (х^2+2х)=0x+1=0x=-1x²+2x=0x(x+2)=0x=-2 x=0(Х^2+3х+1)(х^2+3х+3)=-1(x²+3x+1)(x²+3x+3)+1=0(t+1)(t+3)+1=0(t²+3t+t+3)+1=0(t²+4t+3)+1=0t²+4t+3+1=0t²+4t+4=0D=b²-4ac=4²-4*1*4=0t₁.₂=-b/2a=-4/2*1=-2x²+3x=-2x²+3x+2=0X₁.₂-b+-√D/2ax₁=-3-1/2*1=-2 x₂=-3+1/2*1=-1x=-2 x=-1(Х^2-4х+1)(х^2-4х+2)=12(t+1)(t+2)-12=0(t²+2t+t+2)-12=0(t²+3t+2)-12=0t²+3t+2-12=0D=b²-4ac=3²-4*1(-10)=49t₁.₂=-b+-√D/2at₁=-3-7/2*1=-5 t₂=-3+7/2*1=2x²-4x=-5 x²-4x=2x²-4x=-5x²-4x+5=0x²-4x=2x²-4x-2=0D=b²-4ac=(-4)²=4*1(-2)=24x₁.₂=-b+-√D/2ax₁=4-2√6/2*1=2-√6 x₂=4+2√6/2*1=2+√6x=2-√6 x=2+√6ответ:x=2-√6 x=2+√6(х^2+1)(х^2+2х)=12(x²+1)(x²+2x)-12=0(x^4+2x³+x²+2x)-12=0x^4+2x³+x²+2x-12=0