(x+3)^4-13(x+3)^2+36=0

(x+3)^4-13(x+3)^2+36=0t²-13t+36=0D=b² -4ac=(-13)² -4*1*36=25t₁.₂=-b+-√D/2at₁13-5/2*1=4 t₂=13+5/2*1=9(x+3)²=4 (x+3)²=9(x+3)²-4=0x+3=2x=2-3x=-1x+3=-2x=-2-3x=-5x=-5 x=-1(x+3)²=9(x+3)²-9=0x+3=3x=3-3x=0x+3=-3x=-3-3x=-6ответ:x=-6 x=-5 x=-1 x=0