решите систему уравнений х+у=3, ху+4=0. методом подстановки

решите систему уравнений х+у=3, ху+4=0. методом подстановки
- Предмет:
  Алгебра
- Автор:
  roscoekt1q
- 5 лет назад

Ответы 1

х + у = 3 → х = 3-уху + 4 = 0 → у(3-у) + 4 = 0 3у - у^2 + 4 = 0 y^2 - 3y - 4 = 0 D = 9 - 4*(-4) = 9 + 16 = 25; √D = 5 y1 = (3+5)/2 = 4 y2 = (3 - 5)/2 = -1x = 3 - yx1 = 3 - y1 → 3 - 4 = -1x2 = 3 - y2 → 3 + 1 = 4Ответ: х1 = -1 у1 = 4 х2 = 4 у2 = - 1
- Автор:
  ashesbaker
- 5 лет назад
- 0
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решите систему уравнений х+у=3, ху+4=0. методом подстановки

Ответы 1

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