4^x-5*2^x+4=0 решение уравнений

4^x  - 5*2^x + 4 = 0 2^x = tt^2  - 5t + 4 = 0 D = 25 - 16 = 9 t1 = (5 + 3)/2 = 8/2 = 4;t2 = (5 - 3)/2 = 2/2 = 1;2^x = 42^x = 2^2x = 22^x = 12^x = 2^0x = 0 

2^2x -5*2^x+4=02^x=aa²-5a+4=0a1+a2=5 U a1*a2=4a1=1⇒2^x=1⇒x=0a2=4⇒2^x=4⇒x=2Ответ x=0;x=2