до завтра!помогите,буду благодарна

1. Решите уравнение а) [tex] \sqrt{3} [/tex] ctg [tex] \frac{x}{2} [/tex] = 3
б) sin ([tex] \frac{ \pi }{6} [/tex] - 2x) = 0

a) √3ctg(x/2) = 3ctg(x/2) = 3/√3ctg(x/2) = √3x/2 = π/6 + πk, k€Zx = π/12 + πk/2, k€Z.b) sin(π/6 - 2x) = 0-sin(2x - π/6) = 0sin(2x - π/6) = 0-π/6 + 2x = πk, k€Z2x = π/6 + πk, k€Zx = π/12 + πk/2, k€Z.