Помогите решить очень надо log8 128 + log4 16. 2) log3 9 –log9 27.

log8 (128) + log 4(16) =  1/3 * log2(128) + 1/2* log2 (16) = = log2 (128)^(1/3) + log2 (16)^(1/2) = = log 2 (128^(1/3) * 4) = = log 2 (2^(7/3) * 4) = = log 2 ( 2^(7/3 + 2) ) =  = log2  ( 2^(7/3+6/3) ) = = log 2  ( 2^(13/3) ) = = 13/3log3 (9) - log 9 (27) = = log3 (9) -  log3 (27)^(1/2) = = log3 (9/√27) = = log3  (3^(1/2)) = = 1/2 = 0,5