Решите систему уравнений
x^2-y^2=12
x+y/x-y=3

x≠yx+y=3(x-y)x²-y²=12(x-y)(x+y)=123(x-y)²=12!x-y!=21/ x-y=2x+y=62x=8x=4y=22/ x-y=-2x+y=-62x=-8x=-4y=-2(4 2 )(-4 -2)