Решить уравнение 1. 3x²-16x=0 2. x²+7=0 3. 7x² = 1

Решить уравнение
1. 3x²-16x=0

2. x²+7=0

3. 7x² = 1
- Предмет:
  Алгебра
- Автор:
  elliott40
- 5 лет назад

Ответы 1

3x²-16x=0,х(3х-16)=0,х=0, 3х-16=0, х= $\frac{16}{3}$ = $5 \frac{1}{3}$ Ответ: 0; $5 \frac{1}{3}$ х²+7=0,х²=-7,х=±√-7х= нет решений.Ответ: нет решений.7x² = 1,х²= $\frac{1}{7}$ х= $б\frac{ \sqrt{7} }{7}$ х= $\frac{ \sqrt{7} }{7}$ х= $- \frac{ \sqrt{7} }{7}$ Ответ: $- \frac{ \sqrt{7} }{7}$ ; $\frac{ \sqrt{7} }{7}$ .
- Автор:
  marcelvaughan
- 5 лет назад
- 0
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Решить уравнение 1. 3x²-16x=0 2. x²+7=0 3. 7x² = 1

Ответы 1

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Решить уравнение
1. 3x²-16x=0

2. x²+7=0

3. 7x² = 1