сравните
2√7 и 7√2
3√120 и 2√270
[tex] \frac{1}{2} [/tex]√6 и 6√[tex] \frac{1}{2}[/tex]

2√7 < 7√2√(2²*7) < √(7²*2)√28 < √983√120=√(3²*120)=√(9*120)=√10802√270=√(2²*270)=√(4*270)=√10803√120=2√2701/2*√6=√(1/4*6)=√(6/4)=√1,56√(1/2)=√(36*1/2)=√181/2√6<6√(1/2)