упростите выражение
([tex] \frac{2x+1}{x^2-3x} - \frac{2x-1}{x^2+3x} [/tex])·[tex] \frac{x^2-9}{7x} [/tex]+1

( (2x+1)/x(x-3) - (2x-1)/x(x+3)) = [(2x+1)(x+3) - (2x-1)(x-3)]/x(x-3)(x+3)= (2x²+ 6x +x +3 - 2x² + 6x+x-3) / x(x-3)(x+3) = 14x / x(x-3)(x+3) = 14/(x²-9)14/(x²-9) * (x²-9)/7x +1= 2/x+1=(x+2)/x