2log5 (x) +log5 (16) =4
Как решить??

2log5 (x) +log5 (16) =42 log5(x)+log5(16)=4,х>0log5(x^2)+log5(16)=4log5(x^2*16)=4log5(16x^2)=416x^2=625x=25/4= 6 1/4=6.25