Найдите m и n (подбором)
401*5=(m-n)(m+n)

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Решение смотри на фото

Решения в целых числах составляются восемью системами уравнений:m – n = 401 и m + n = 5.m = 203 и n = –198.m – n = –401 и m + n = –5.m = –203 и n = 198.m – n = 5 и m + n = 401.m = 203 и n = 198.m – n = –5 и m + n = –401.m = –203 и n = –198.m – n = 2005 и m + n = 1.m = 1003 и n = –1002.m – n = –2005 и m + n = –1.m = –1003 и n = 1002.m – n = 1 и m + n = 2005.m = 1003 и n = 1002.m – n = –1 и m + n = –2005.m = –1003 и n = –1002.Ответ: (m, n) = (±1003, ±1002) = (±203, ±198).