Решите уравнение
log5 (√3x+4)*log(x) 5 =1

ОДЗ3x+4>0⇒x>-4/3 U x>0 U x≠1x∈(0;1) U(1;∞)log(5)√(3x+4)*1/log(5)x=1log(5)√(3x+4) = log(5)xlog(5)√(3x+4)-log(5)x=0log(5)√(3x+4)/x=0√(3x+4)/x=1√(3x+4)=x3x+4=x²x²-3x-4=0x1+x2=3 U x1*x2=-4x1=-1∉ОДЗx2=4