решите уравнение
(х +1)^2=0
(х-2)^2=64

(x  + 1)^2 = 0x + 1 = 0 x = -  1==============================================(x - 2)^2 - 64 =  0(x -  2)^2 - 8^2 = 0 (x - 2  - 8)(x - 2 + 8) = 0(x - 10)( x + 6) = 0x - 10 = 0x  = 10;x + 6 = 0x = - 6 

(х+1)²=0х²+2х+1=0D=4-4=0x=-2/2=-1(x-2)²=64x²-4x+4-64=0x²-4x-60=0D=16+240=256       √D=16x₁=(4+16)/2=10x₂=(4-16)/2=-6