постройте график функции у=х^2-5х+4

постройте график функции у=х^2-5х+4
- Предмет:
  Алгебра
- Автор:
  rosalia3e5c
- 5 лет назад

Ответы 1

Парабола, ветви вверх. Нули функции - точки пересечения с ОХ: $x^{2} -5x+4=0 \\ (x-1)(x-4)=0 \\ x=1,x=4$ $x_0=\frac{-b}{2a} = \frac{5}{2} =2,5 \\ y_0=2,5^2-5*2,5+4=6,25-12,5+4=-2,25$ Вершина параболы: $(2,5;-2,25)$ Точка пересечения с осью Y: $y(0)=0^2-5*0+4=4 \\ (0;4)$ Берем несколько дополнительных точек для более точного построения: $(2;-2),(3;-2),(5;4)$
- Автор:
  makailaedu5
- 5 лет назад
- 0
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постройте график функции у=х^2-5х+4

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