Найдите произведение корней уравнения: (3x+1)(2x^2+x-3)=0

(3x + 1)(2x^2 + x - 3) = 01) 3x + 1 = 0 3x = - 1x1 = - 1/32) 2x^2 + x - 3 = 0 D = 1 + 24 = 25x2 = ( - 1 + 5)/4 = 1x3 = ( - 1 - 5)/4 = - 3/2 = - 1,5x1*x2*x3 = (-1/3)*1*(-3/2) = 0,5