решите пожалуйста 8 класс , алгебра , можнл с решением

4 3m–7 1–6m-------- + ------------- = -------------------3m+1 27m^3+1 1–3m+9m^2 4 3m–7 -------- + ----------------------------- –3m+1 (3m+1)(9m^2–3m+1) 1–6m– ------------------ = 0 1–3m+9m^236m^2–12m+4+3m–7–3m+18m^2–---------------------------------------------------- (3m+1)(9m^2–3m+1)–1+6m---------- = 0 54m^2–6m–4---------------------------- = 0(3m+1)(9m^2–3m+1) (3m+1)(9m^2–3m+1)=0 (не равно 0)3m+1=03m=–1m=–1/39m^2–3m+1=0Д=/9–4*9*1 решений нет Д<054m^2–6m–4 = 0Д=/36–4*54*(-4)=/900=30m1=(6+30)/108=36/108=1/3m2=(6–30)/108=–24/108 = –6/27Ответ: m1=1/3; m2=–6/27