решите уравнение 6sin^2x=5sinxcosx-cos^2x

Решение6sin^2x=5sinxcosx-cos^2x 6sin^2x - 5sinxcosx  + cos^2x = 0 делим на ²x ≠ 06tg²x - 5tgx + 1 = 0tgx = t6t² - 5t + 1 = 0D = 25 - 4*6*1 = 1t = (5-1)/12t = 1/3t = (5+1)/12t = 1/21)  tgx = 1/3x ₁= arctg(1/3) + πk, k ∈ Z2)  tgx = 1/2x₂ = arctg(1/2) + πn, n ∈Z