решите через дескриминат
1) (х-2)(12-х)=9
2) (х+1)^2=3(х+7)

(х-2)(12-х)=912x-x^2-24+2x=914x-x^2-24-9=0x^2-14x+33=0D=(-14)^2-4*1*33==196-132=64=8^2x1=(14+8)/2=11x2=(14-8)/2=3==========================================================(х+1)^2=3(х+7)x^2+2x+1=3x+21x^2+2x+1-3x-21=0x^2-x-20=0D=(-1)^2-4*1*(-20)=1+80=81=9^2x1=(1+9)/2=5x2=(1-9)/2=-4