Представьте в виде многочлена
2. 5а2(4а3-а2+1)
3. (1-х)(2у +х)
4. (5с – 4)2

5a^2(4a^3-a^2+1)==5a^2*4a^3-5a^2*a^2+5a^2==20a^5-5a^4+5a^2====================(1-x)(2y+x)==2y+x-x*2y-x*x==2y+x-2xy-x^2=====================(5c-4)^2==(5x)^2-2*5c*4+4^2==25c^2-40c+16