Решите уравнение (2х-1)(3х+5)=2х-1

(2x - 1)(3x + 5) = 2x - 16x² - 3x + 10x - 5 - 2x + 1 = 06x² + 5x - 4 = 0D = 25 + (-4) * 6 * (-4) = 121√D = 11x₁ = (-5 + 11)/12 = 1/2x₂ = (-5 - 11)/12 = -4/3Ответ: -4/3; 1/2

(2х-1)(3х+5)=2х-16x^2+10x-3x-5=2x-16x^2+7x-5=2x-16x^2+7x-5-2x+1=06x^2+5x-4=0D=25+96=121=11^2x=(-5+-11)/12x1=0.5x2=-(4/3)