решите уравнение
12-(4-х)^2=х(3-х)

12-(16-8x+x^2)=3x-x^2, 12-16+8x-x^2-3x+x^2=0,-4+5x=0, 5x=4, x=4:5, x=0,8.

(a-b)^2 = a^2 -2ab +b^212-(4-х)^2=х(3-х) 12 -(16 -8x +x^2) = 3x -x^212 -16 +8x -x^2 = 3x -x^2-4 +8x -x^2 -3x +x^2 = 05x -4 = 05x = 4x = 4/5