решите систему {х-у=1 х²-у=3

x = y + 1(y + 1)^2 - y = 3**y^2 + 2y + 1 - y - 3 = 0y^2 + y - 2 = 0 D = 1 + 8 = 9 y1 = ( - 1 + 3)/2 = 1y2 = ( - 1 - 3)/2 = - 2x1 = y1 + 1 = 1 + 1 = 2y1 = 1x2 = y2 + 1 = - 2 + 1 = - 1y2 = - 2 Ответ ( - 1 ; - 2)  (2; 1)