√(х+5 ) +√(2х+8) =7
решите иррационльное уравнение

√ ( x + 5 ) + √ ( 2x + 8 ) = 7 ( √ ( x + 5 ) + √ ( 2x + 8 ))^2 = 7^2 x + 5 + 2x + 8 + 2√ ( x + 5 )( 2x + 8 ) = 49 2√ ( 2x^2 + 8x + 10x + 40 ) = 49 - 3x - 13 √ ( 2x^2 + 18x + 40 ) = ( 36 - 13x ) : 2 √ (2x^2 + 18x + 40 ) = 18 - 7,5x ( √ ( 2x^2 + 18x + 40 ))^2 = ( 18 - 7,5x )^2 2x^2 + 18x + 40 = 324 - 270x + 56,25x^254,25x^2 - 288x + 284 = 0 D = 82944 - 61628 = 21316 = 146^2 x1 = ( 288 + 146 ) : 108,5 = 4 x2 = ( 288 - 146 ) : 108,5 = 142 : 108,5 = 1420/1085 = 1 335/1085 = 1 67/217 x + 5 ≥ 0 ;  х ≥ - 5 2х + 8 ≥ 0 ; 2x ≥ - 8 ; x ≥ - 4