Решите уравнение:
1-2cos^2(4x-п/4)=0

1 - 2cos²(4x - π/4) = 0cos²(4x - π/4) = 1/2cos(4x - π/4) = ±√2/21) cos(4x - π/4) = √2/24x - π/4 = ±π/4 + 2πn, n ∈ Z4x = ±π/4 + π/4 + 2πn, n ∈ Zx = ±π/16 + π/16 + πn/2, n ∈ Z2)cos(4x - π/4) = -√2/24x - π/4 = ±3π/4 + 2πn, n ∈ Z4x = ±3π/4 + π/4 + 2πn, n ∈ Zx = ±3π/16+ π/16 + πn/2, n ∈ Z