(а2-7а+12)х=а-3 Помогите решить

(а2-7а+12)х=а-3 Помогите решить
- Предмет:
  Алгебра
- Автор:
  andreasewing
- 5 лет назад

Ответы 1

$(a^2-7a+12)x=a-3$ $(a-3)(a-4)x=a-3$ при а=3: $0x=0$ - решением будет любое действительное числопри a=4: $0x=1$ - решений нетпри $a eq 3; a eq 4$ - $x=\frac{1}{a-4}$ ответ: при а=3 - х є $(-\infty;+\infty)$ при а=4 x є $\varnothing$ при $a eq 3; a eq 4$ : $x=\frac{1}{a-4}$
- Автор:
  sarai
- 5 лет назад
- 0
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(а2-7а+12)х=а-3 Помогите решить

Ответы 1

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