Решите уравнение
1) 3x^2-4x=0
2) x^3-x^2-x+1=0

1)3x^2 - 4x = 0 x (3x - 4) = 0 x = 0 ;3x - 4 = 0 => 3x = 4 => x = 4/3Ответ 0; 4/32)x^3 - x^2 - x + 1 = 0 x^2 (x - 1) - 1(x - 1) = 0 (x - 1)(x^2 - 1) = 0 x - 1 = 0 ==> x = 1;x^2 - 1 = 0 => x^2 = 1 ==> x = ± 1Ответ - 1; 1