Решите уравнение:
x(x²+x-12)=5(x-3).

x(x2+x–12)=5(x–3). x1=(–1–7)/2=–4x2=(–1+7)/2=3x2+x–12=(x+4)(x–3)x(x+4)(x–3)–5(x–3)=0(x–3)(x2+4x–5)=0. x–3=0 или x2+4x–5=0x1=3 D=16+20=36x2=(–4–6)/2=–5x3=(–4+6)/2=1