3.(x-5)(x+3)(x+2)>0x=5 x= -3 x= -2 - + - +---------- -3 ------------ -2 ------------- 5 ------------- \\\\\\\\\\\\\\\ \\\\\\\\\\\\\\x∈(-3; -2)U(5; +∞)4.ОДЗ: x≠5(x+2)(x-5)≤0x= -2 x=5 + - +--------- -2 ----------- 5 ---------------- \\\\\\\\\\\\\\x∈[-2; 5)5.ОДЗ: x≠5(2x-3)(x+7)(x-5)≥02(x-1.5)(x+7)(x-5)≥0(x-1.5)(x+7)(x-5)≥0x=1.5 x= -7 x=5 - + - +--------- -7 ---------- 1.5 ----------- 5 ------------ \\\\\\\\\\\ \\\\\\\\\\\\x∈[-7; 1.5]U(5; +∞)6.ОДЗ: x≠ -5, x≠5Разложим на множители:x²-2x-35=(x+5)(x-7)x²-2x-35=0D=(-2)²-4*(-35)=4+140=144=12²x₁=(2-12)/2= -10/2= -5x₂=(2+12)/2=14/2=7Сокращаем:[(x+5)(x-7)]/[(x-5)(x+5)]≥0(x-7)/(x-5) ≥ 0(x-7)(x-5)≥0x=7 x=5 + - +---------- 5 ----------- 7 -----------\\\\\\\\\\\ \\\\\\\\\\x∈(-∞; 5)U[7; +∞)