Помогите решить систему неравенств:
x^2-5x-14>0
x^2-2x-35<0

1) х²-5х-14 > 0D = 25+56 = 81x₁= 5-9 / 2 = -2x₂= 5+9 / 2 = 7       +         -         +--------₀--------₀------->x\\\\\\\ -2       7 /////////2) х²-2х-35 < 0D = 4+140 = 144x₁ = 2-12 / 2 = -5x₂ = 2+12 / 2 = 7         +           -           +----------₀---------₀-------->x          -5 //////// 7\\\\\\\\\\\\\\ -2                  7 /////////------₀---------₀----------------₀------->x      -5 \\\\\\\\\\\\\\\\\\\\\\\ 7x∈(-5; -2)